JEE Main 5 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

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Question : 16 of 90

Marks: +1, -0

If ‌

1

√1+√2

+‌

1

√2+√3

+...+‌

1

√99+√100

=m and ‌

1

1⋅2

+‌

1

2⋅3

+...+‌

1

99⋅100

=n, then the point (m,n) lies on the line

[5 Apr 2024 Shift 1]

11(x−1)−100(y−2)=0
11(x−2)−100(y−1)=0
11(x−1)−100y=0
11x−100y=0

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