Two liquids A and B have \theta_A and \theta_B as contact angles in a capillary tube. If K=\frac{\cos \theta_A}{\cos \theta_B}, then identify the correct statement: [4 Apr 2025 Shift 1]

Correct Answer is : K is negative, then liquid A has concave meniscus and liquid B has convex meniscus.

K is negative, then liquid A has concave meniscus and liquid B has convex meniscus.

K is zero, then liquid A has convex meniscus and liquid B has concave meniscus.

K is negative, then liquid A and B have convex meniscus.

K is negative, then liquid A and liquid B have concave meniscus.

JEE Main 4 Apr 2025 Shift 1 Paper

Section: Physics

Question : 43 of 75

Marks: +1, -0

Two liquids A and B have θA and θB as contact angles in a capillary tube. If K=‌

cos‌θA

cos‌θB

, then identify the correct statement:

[4 Apr 2025 Shift 1]

K is negative, then liquid A has concave meniscus and liquid B has convex meniscus.
K is zero, then liquid A has convex meniscus and liquid B has concave meniscus.
K is negative, then liquid A and B have convex meniscus.
K is negative, then liquid A and liquid B have concave meniscus.

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