JEE Main 4 Apr 2025 Shift 1 Paper

Section: Mathematics

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Question : 17 of 75

Marks: +1, -0

Let the shortest distance between the lines ‌

x−3

3

=‌

y−α

−1

=‌

z−3

1

and ‌

x+3

−3

=‌

y+7

2

=‌

z−β

4

be 3√30. Then the positive value of 5α+β is

[4 Apr 2025 Shift 1]

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