JEE Main 4 Apr 2024 Shift 2 Solved Paper

Section: Mathematics

© examsiri.com

Question : 7 of 90

Marks: +1, -0

The value of ‌

1×22+2×32+...+100×(101)2

12×2+22×3+...+1002×101

is

[4 Apr 2024 Shift 2]

‌
306
305
‌
305
301
‌
32
31
‌
31
30

Go to Question:

Prev Question

Next Question