JEE Main 4 Apr 2024 Shift 2 Solved Paper
© examsiri.com
Question : 55 of 90
Marks:
+1,
-0
The disintegration energy Q 235 U ⟶ 140 Ce + 94 Zr + n MeV
Given atomic masses of
235 U : 235.0439 u ; 140 Ce ; 139.9054 u ,
94 Zr : 93.9063 u ; n : 1.0086 u ,
Value ofc 2 = 931 MeV ∕ u
Given atomic masses of
Value of
[4 Apr 2024 Shift 2]
- Your Answer:
Go to Question: