If the mean of the following probability distribution of a random variable {\X}; X 0 2 4 6 8 P(X) a 2a a+b 2b 3b is \frac{46}{9}, then the variance of the distribution is [4 Apr 2024 Shift 2]

JEE Main 4 Apr 2024 Shift 2 Solved Paper

Section: Mathematics

Question : 15 of 90

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If the mean of the following probability distribution of a random variable X;

X	0	2	4	6	8
P(X)	a	2a	a+b	2b	3b

is ‌

, then the variance of the distribution is

[4 Apr 2024 Shift 2]

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