If the solution y=y(x) of the differential equation ( {\x}^4+2 {\x}^3+3 {\x}^2+2 {\x}+2) {\dy}- (2 {\x}^2+2 {\x}+3) {\dx}=0 satisfies y(-1)=-\frac{\pi}{4}, then y(0) is equal to : [4 Apr 2024 Shift 1]

JEE Main 4 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 4 of 90

Marks: +1, -0

If the solution y=y(x) of the differential equation (x4+2x3+3x2+2x+2)‌dy−(2x2+2x+3)‌dx=0 satisfies y(−1)=−‌

, then y(0) is equal to :

[4 Apr 2024 Shift 1]

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