The electric field in an electromagnetic wave is given by { {\E}}^{\to}=\stackrel{\^}{ {\i}} 40 \cos \omega ( {\t}- { {\z}}/{ {\c}}) N C^{-1}. The magnetic field induction of this wave is (in SI unit): [4 Apr 2024 Shift 1]

Correct Answer is : →B=^j40ccosω(t−zc)

{ {\B}}^{\to}=\stackrel{\^}{ {\i}} \frac{40}{ {\c}} \cos \omega ( {\t}- { {\z}}/{ {\c}})

\overrightarrow{B}=\stackrel{\^}{j} 40 \cos \omega (t-\frac{z}{c})

{ {\B}}^{\to}=\stackrel{\^}{ {\k}} \frac{40}{ {\c}} \cos \omega ( {\t}- { {\z}}/{ {\c}})

\overrightarrow{B}=\stackrel{\^}{j} \frac{40}{c} \cos \omega (t-\frac{z}{c})

JEE Main 4 Apr 2024 Shift 1 Solved Paper

Section: Physics

Question : 32 of 90

Marks: +1, -0

The electric field in an electromagnetic wave is given by

→

40‌cos‌ω(t−‌

)‌N‌C−1. The magnetic field induction of this wave is (in SI unit):

[4 Apr 2024 Shift 1]

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