JEE Main 4 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

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Question : 14 of 90

Marks: +1, -0

If 2 and 6 are the roots of the equation ax2+bx+1=0, then the quadratic equation, whose roots are ‌

1

2a+b

and ‌

1

6a+b

, is :

[4 Apr 2024 Shift 1]

2x2+11x+12=0
4x2+14x+12=0
x2+10x+16=0
x2+8x+12=0

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