Let f: {\R} \rightarrow {\R} be a function given by f(x)={\\begin{array}{c}\\\{1-\cos 2 x\end\frac{array}{x^2} ,{, } x < 0 ; \alpha ,{, } x=0 ; {\beta \sqrt{1-\cos x}}/{x} ,{, } x > 0},where \alpha, \beta \in {\R}. If f is continuous at {\x}=0, then \alpha^2+\beta^2 is equal to : [4 Apr 2024 Shift 1]

JEE Main 4 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 1 of 90

Marks: +1, -0

Let f:R⟶R be a function given by
f(x)={

‌

1−cos‌2‌x

,‌x<0

,‌x=0

‌

β√1−cos‌x

,‌‌‌x>0

,where α,β∈R. If

f is continuous at x=0, then α2+β2 is equal to :

[4 Apr 2024 Shift 1]

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