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Question : 26 of 90
Marks:
+1,
-0
Solution:
‌(+)×=2(×) +24−6 ‌(5++4)×=2(7−7−7) +24−6 ‌||=14+10−20 ‌⇒(z−4y)−(5z−4x)+(5y−x) =14+10−20 ‌z−4y=14,4x−5z=10, 5y−x=−20 ‌(a−b+i)⋅=−3 ‌(2+3−2)⋅=−3 ‌2x+3y−2z=−3 ‌∴x=5,y=−3,z=2 ‌||2=25+9+4=38
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