The shortest distance between lines {\L}_1 and {\L}_2, where L_1: \frac{x-1}{2}=\frac{y+1}{-3}=\frac{z+4}{2} and L_2 is the line passing through the points {\A}(-4,4,3) \cdot {\B}(-1,6,3) and perpendicular to the line \frac{x-3}{-2}=\frac{y}{3}=\frac{z-1}{1}, is [31-Jan-2024 Shift 2]

JEE Main 31-Jan-2024 Shift 2 Solved Paper

Section: Mathematics

Question : 20 of 90

Marks: +1, -0

The shortest distance between lines L1 and L2, where L1:‌

x−1

=‌

y+1

−3

=‌

z+4

and L2 is the line passing through the points A(−4,4,3)⋅B(−1,6,3) and perpendicular to the line ‌

x−3

−2

=‌

z−1

, is

[31-Jan-2024 Shift 2]

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