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JEE Main 31-Jan-2024 Shift 1 Solved Paper

Section: Mathematics
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Question : 30 of 90
 
Marks: +1, -0
Let f:ℝ→ℝ be a function defined by f(x)=‌
4x
4x+2
 and
M=
f(1−a)
∫
f(a)
xsin‌4(x(1−x))‌dx
N=
f(1−a)
∫
f(a)
sin‌4(x(1−x))‌dx;a≠‌
1
2
.‌ If ‌
αM=βN,α,β∈ℕ, then the least value of α2+β2 is equal to
[31-Jan-2024 Shift 1]
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