Let \alpha, \beta, \gamma, \delta \in {\Z} and let {\A}(\alpha, \beta), {\B}(1,0), {\C}(\gamma, \delta) and {\D}(1,2) be the vertices of a parallelogram A B C D. If A B=\sqrt{10} and the points A and C lie on the line 3 y=2 x+1, then 2(\alpha+\beta+\gamma+\delta) is equal to [31-Jan-2024 Shift 1]

JEE Main 31-Jan-2024 Shift 1 Solved Paper

Section: Mathematics

Question : 10 of 90

Marks: +1, -0

Let α,β,γ,δ∈Z and let A(α,β),B(1,0),C(γ,δ) and D(1,2) be the vertices of a parallelogram ABCD. If AB=√10 and the points A and C lie on the line 3y=2x+1, then 2(α+β+γ+δ) is equal to

[31-Jan-2024 Shift 1]

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