If \\alpha+\\beta+\\gamma=2 \\pi, then the system of equations x+(\cos \\gamma) y+(\cos \\beta) z=0 (\cos \\gamma) x+y+(\cos \\alpha) z=0 (\cos \\beta) x+(\cos \\alpha) y+z=0 has : [31 Aug 2021 Shift 2]

Correct Answer is : infinitely many solution

JEE Main 31-Aug-2021 Shift 2 Solved Paper

Section: Mathematics

Question : 61 of 90

Marks: +1, -0

If α+β+γ=2π, then the system of equations
x+(cos‌γ)y+(cos‌β)z=0
(cos‌γ)x+y+(cos‌α)z=0
(cos‌β)x+(cos‌α)y+z=0
has :

[31 Aug 2021 Shift 2]

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