JEE Main 31-Aug-2021 Shift 1 Solved Paper

Enthalpy change of the reaction, A + B → M + N in kJ/mol is given as
Enthalpy change (∆H) = Activation energy of forward reaction – Activation energy of backward reaction
ΔH=Ea(f)−Ea(b)
=x−(x+y)
=20−(20+45)
=−45‌kJ‌mol−1