A uniform heavy rod of weight 10 {\kg} {\ms}^{-2}, cross-sectional area 100 {\cm}^{2} and length 20 {\cm} is hanging from a fixed support. Young's modulus of the material of the rod is 2 \times10^{11} {\Nm}^{-2}. Neglecting the lateral contraction, find the elongation of rod due to its own weight. [31 Aug 2021 Shift 1]

Correct Answer is : 5×10−10m

JEE Main 31-Aug-2021 Shift 1 Solved Paper

Section: Physics

Question : 12 of 90

Marks: +1, -0

A uniform heavy rod of weight 10‌kg‌ms−2, cross-sectional area 100cm2 and length 20‌cm is hanging from a fixed support. Young's modulus of the material of the rod is 2×1011Nm−2. Neglecting the lateral contraction, find the elongation of rod due to its own weight.

[31 Aug 2021 Shift 1]

2×10−9m
5×10−8m
4×10−8m
5×10−10m

Validate

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