JEE Main 30 June 2022 Shift 1 Solved Paper

At‌t=20 s
velocity of truck,
v=0+5×20=100m∕ s
At 20 sec a ball is dropped from the truck, so velocity of ball will be same as truck.
Velocity of truck at x-direction =100m∕ s and in y-direction =0.
∴ Velocity of ball vx=100m∕ s,vy=0
Now ball will show projectile motion where vertically downward acceleration g=10m∕ s act on the ball.
As horizontally no acceleration acting on the ball so horizontal velocity 100m∕ s will remain unchanged.
Velocity of the ball when it reach the ground along y-direction after 1 sec.
vy=0−10×1
⇒vy=−10m∕ s
∴ Velocity of ball (

→

v

)=100

^

i

−10

^

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