JEE Main 30-Jan-2024 Shift 2 Solved Paper

Section: Physics

Question : 38 of 90

Marks: +1, -0

An alternating voltage V(t)=220sin‌100πt volt is applied to a purely resistive load of 50Ω. The time taken for the current to rise from half of the peak value to the peak value is:

[30-Jan-2024 Shift 2]

5‌ms
3.3‌ms
7.2‌ms
2.2‌ms

Validate

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