JEE Main 30-Jan-2024 Shift 2 Solved Paper
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Question : 12 of 90
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Let f : R → R f ( x ) = a e 2 x + b e x + c x f ( 0 ) = − 1 , f ′ ( log e 2 ) = 21
log e 4 ( f ( x ) − c x ) dx =
| a + b + c |
[30-Jan-2024 Shift 2]
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