Compound A formed in the following reaction reacts with B gives the product C. Find out A and B. {\CH}_3- {\C} \equiv {\CH}+ {\Na} \to \bo{\A} \to^{\bo{\B}} {\CH}_3- {\C} \equiv_{\bo(\C)} {\C}- {\CH}_2- {\CH}_2_{| }_{CH_3}+ {\NaBr} [30-Jan-2024 Shift 1]

Correct Answer is : A=CH3−C≡CN+a,B=CH3−CH2−CH2−Br

{\A}= {\CH}_3- {\C} \equiv \overline{ {\C}} \stackrel{+}{\N{a}}, {\B}= {\CH}_3- {\CH}_2- {\CH}_2- {\Br}

{\A}= {\CH}_3- {\CH}= {\CH}_2, {\B}= {\CH}_3- {\CH}_2- {\CH}_2- {\Br}

{\A}= {\CH}_3- {\CH}_2- {\CH}_3, {\B}= {\CH}_3- {\C} \equiv {\CH}

{\A}= {\CH}_3- {\C} \equiv \overline{\C}N \stackrel{+}{\a}, {\B}= {\CH}_3- {\CH}_2- {\CH}_3

JEE Main 30-Jan-2024 Shift 1 Solved Paper

Section: Chemistry

Question : 77 of 90

Marks: +1, -0

Compound A formed in the following reaction reacts with B gives the product C. Find out A and B.

CH3−C≡CH+Na→A

→

CH3−C

≡

(C)

C−CH2−

CH2

|‌‌‌‌‌

CH3

+NaBr

[30-Jan-2024 Shift 1]

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