JEE Main 3 Apr 2025 Shift 2 Paper
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Question : 19 of 75
Marks:
+1,
-0
Let y = y ( x )
+ 3 ( tan 2 x ) y + 3 y = s e c 2 x , y ( 0 ) =
+ e 3 y (
)
[3 Apr 2025 Shift 2]
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