JEE Main 3 Apr 2025 Shift 1 Paper

Section: Mathematics

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Question : 7 of 75

Marks: +1, -0

Let f(x)={

(1+ax)1∕x

,‌x<0

1+b

,‌x=0

‌

(x+4)1∕2−2

(x+c)1∕3−2

,‌x>0

be continuous at x=0. Then eabc is equal to:

[3 Apr 2025 Shift 1]

48
72
36
64

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