JEE Main 29 June 2022 Shift 2 Solved Paper
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Question : 9 of 90
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If y = y ( x ) is the solution of the differential equation ( 1 + e 2 x )
+ 2 ( 1 + y 2 ) e x = 0 and y ( 0 ) = 0 then 6 ( y ′ ( 0 ) + ( y ( log e √ 3 ) ) 2 ) is equal to
[29-Jun-2022-Shift-2]
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