JEE Main 29 June 2022 Shift 2 Solved Paper

Section: Mathematics

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Question : 5 of 90

Marks: +1, -0

The value of

lim

x→1

‌

(x2−1)sin2(πx)

x4−2x3+2x−1

is equal to:

[29-Jun-2022-Shift-2]

‌
π2
6
‌
π2
3
‌
π2
2
π2

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