JEE Main 29 June 2022 Shift 2 Solved Paper
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Question : 26 of 90
Marks:
+1,
-0
Let f and g be twice differentiable even functions on ( − 2 , 2 ) such that f (
) = 0 , f (
) = 0 , f ( 1 ) = 1 and g (
) = 0 , g ( 1 ) = 2 . Then, the minimum number of solutions of f ( x ) g ′ ′ ( x ) + f ′ ( x ) g ′ ( x ) = 0 in ( − 2 , 2 ) is equal to____
[29-Jun-2022-Shift-2]
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