JEE Main 29 June 2022 Shift 1 Solved Paper
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Question : 85 of 90
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The activation energy of one of the reactions in a biochemical process is 532611 J mol − 1 . When the temperature falls from 310 K to 300 K , the change in rate constant observed is k 300 = x × 10 − 3 k 310 . The value of x is______
[Given. : ln 10 = 2.3 , R = 8.3 JK − 1 mol − 1 ]
[Given
[29-Jun-2022-Shift-1]
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