The area enclosed by y^2=8 x and y=\sqrt{2} x that lies outside the triangle formed by y=\sqrt{2} x, x=1, y=2 \sqrt{2}, is equal to: [29-Jun-2022-Shift-1]

JEE Main 29 June 2022 Shift 1 Solved Paper

Section: Mathematics

Question : 6 of 90

Marks: +1, -0

The area enclosed by y2=8x and y=√2x that lies outside the triangle formed by y=√2x,x=1,y=2√2, is equal to:

[29-Jun-2022-Shift-1]

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