JEE Main 29 June 2022 Shift 1 Solved Paper

Section: Physics

Question : 31 of 90

Marks: +1, -0

Two balls A and B are placed at the top of 180m tall tower. Ball A is released from the top at t=0s. Ball B is thrown vertically down with an initial velocity 'u' at t=2s. After a certain time, both balls meet 100m above the ground. Find the value of ' u ' in ms−1⋅[. use .g=10ms−2] :

[29-Jun-2022-Shift-1]

Validate

Go to Question:

Prev Question

Next Question