JEE Main 29 June 2022 Shift 1 Solved Paper

Section: Mathematics
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Question : 28 of 90
 
Marks: +1, -0
Let H:‌
x2
a2
−‌
y2
b2
=1
,a>0
,b>0
, be a hyperbola such that the sum of lengths of the transverse and the conjugate axes is 4(2√2+√14). If the eccentricity H is ‌
√11
2
, then the value of a2+b2 is equal to
[29-Jun-2022-Shift-1]
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