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Question : 22 of 90
Marks:
+1,
-0
Solution:
‌+‌y=xetan−1(√2‌cot‌2‌x)∫‌=∫‌=∫‌=−∫‌‌dt=−∫‌‌dt=‌tan−1(‌)Cot‌x=t=−‌tan−1(√2‌cot‌2‌x) ∴IF=e−tan−1(√2‌cot‌2‌x)ye−tan−1(√2‌cot‌2‌x)=∫xdxye−tan−1(√2‌cot‌2‌x)=‌+cy(‌)=‌+c⇒c=0y=‌etan−1(√2‌cot‌2‌x)y(‌)=‌etan−1(√2‌cot‌)=‌e−tan−1(√‌)α=√‌⇒3α2=2
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