A physical quantity Q is related to four observables a, b, c, d as follows : Q=\frac{a b^4}{c d} where, a=(60 \pm 3) {\Pa} ; b=(20 \pm 0.1) {\m} ; c=(40 \pm 0.2) {\Nsm}^{-2} and d=(50 \pm 0.1) {\m}, then the percentage error in Q is \frac{x}{1000}, where x= ______ . [29 Jan 2025 Shift 2]

JEE Main 29 Jan 2025 Shift 2 Paper

SECTION - B Numerical Value Type Questions: This section contains 5 Numerical based questions. The answer to each question should be rounded-off to the nearest integer.

Section: Physics

Question : 46 of 75

Marks: +1, -0

A physical quantity Q is related to four observables
a,b,c,d as follows :
Q=‌

ab4

where, a=(60±3)‌Pa;b=(20±0.1)m;c=(40± 0.2)‌Nsm−2 and d=(50±0.1)m, then the percentage error in Q is ‌

1000

, where x= ______ .

[29 Jan 2025 Shift 2]

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