Let [f] be the greatest integer less than or equal to t. Then the least value of p \in N for which \lim_{x \rightarrow 0^{+}} (x ( [\frac{1}{x}] + [\frac{2}{x}] +. . .+ [\frac{p}{x}] ) -x^2 ( [\frac{1}{x^2}] + [\frac{2^2}{x^2}] +. . . [\frac{9^2}{x^2}] ) ) \geq 1 is equal to ______ . [29 Jan 2025 Shift 1]

JEE Main 29 Jan 2025 Shift 1 Paper

SECTION - B Numerical Value Type Questions: This section contains 5 Numerical based questions. The answer to each question should be rounded-off to the nearest integer.

Section: Mathematics

Question : 21 of 75

Marks: +1, -0

Let [f] be the greatest integer less than or equal to
t. Then the least value of p∈N for which

lim

x⟶0+

(x([‌

]+[‌

]+...+[‌

])−x2([‌

]+[‌

]+...[‌

]))≥1
is equal to ______ .

[29 Jan 2025 Shift 1]

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