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Question : 18 of 75
Marks:
+1,
-0
Solution:
‌=+2+‌=2+7+3‌L1:=(−+2+)+λ,λ∈R‌‌ and ‌L2=(+)+µ,µ∈R‌+=3+9+4‌L1:=(λ−1)+2(λ+1)+(λ+1)‌L2:=2µ+(7µ+1)+(1+3µ)For point of intersection of
L1&L2‌λ−1=2µ‌ and ‌2(λ+1)=7µ+1‌⇒λ=3‌ and ‌µ=1‌L3:=2+8+4+α(3+9+4)For
α=2=8+26+12
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