Define a relation R on the interval [0, \frac{\pi}{2}) by x R y if and only if \sec ^2 x-\tan ^2 y=1. Then R is: [29 Jan 2025 Shift 1]

Correct Answer is : an equivalence relation

both reflexive and transitive but not symmetric

reflexive but neither symmetric not transitive

both reflexive and symmetric but not transitive

JEE Main 29 Jan 2025 Shift 1 Paper

Section: Mathematics

Question : 1 of 75

Marks: +1, -0

Define a relation R on the interval [0,‌

) by xRy if and only if sec2x−tan2y=1. Then R is:

[29 Jan 2025 Shift 1]

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