The temperature of a gas having 2.0 \times 10^{25} molecules per cubic meter at 1.38 {\atm} (Given, {\k}= 1.38 \times 10^{-23} {\JK}^{-1}) is : [29-Jan-2024 Shift 2]

JEE Main 29-Jan-2024 Shift 2 Solved Paper

Section: Physics

Question : 35 of 90

Marks: +1, -0

The temperature of a gas having 2.0×1025 molecules per cubic meter at 1.38‌atm (Given, k= 1.38×10−23JK−1) is :

[29-Jan-2024 Shift 2]

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