Let (5, \frac{a}{4}), be the circumcenter of a triangle with vertices A(a,-2), B(a, 6) and C (\frac{a}{4},-2). Let \alpha denote the circumradius, \beta denote the area and \gamma denote the perimeter of the triangle. Then \alpha+\beta+\gamma is [29-Jan-2024 Shift 1]

JEE Main 29-Jan-2024 Shift 1 Solved Paper

Section: Mathematics

Question : 9 of 90

Marks: +1, -0

Let (5,‌

), be the circumcenter of a triangle with vertices A(a,−2),B(a,6) and C(‌

,−2). Let α denote the circumradius, β denote the area and γ denote the perimeter of the triangle. Then α+β+γ is

[29-Jan-2024 Shift 1]

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