The resistance {\R}= { {\V}}/{ {\I}} where {\V}=(200 \pm 5) {\V} and {\I}=(20 \pm 0.2) {\A}, the percentage error in the measurement of {\R} is : [29-Jan-2024 Shift 1]

JEE Main 29-Jan-2024 Shift 1 Solved Paper

Section: Physics

Question : 38 of 90

Marks: +1, -0

The resistance R=‌

where V=(200±5)V and I=(20±0.2)A, the percentage error in the measurement of R is :

[29-Jan-2024 Shift 1]

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