Equation of two diameters of a circle are 2 x-3 y=5 and 3 x-4 y=7. The line joining the points (-\frac{22}{7},-4) and (-\frac{1}{7}, 3) intersects the circle at only one point {\P}(\alpha, \beta). Then 17 \beta-\alpha is equal to___ [29-Jan-2024 Shift 1]

JEE Main 29-Jan-2024 Shift 1 Solved Paper

Section: Mathematics

Question : 21 of 90

Marks: +1, -0

Equation of two diameters of a circle are 2x−3y=5 and 3x−4y=7. The line joining the points (−‌

,−4) and (−‌

,3) intersects the circle at only one point P(α,β). Then 17β−α is equal to___

[29-Jan-2024 Shift 1]

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