JEE Main 28 June 2022 Shift 2 Solved Paper

Section: Physics

Question : 45 of 90

Marks: +1, -0

An EM wave propagating in x-direction has a wavelength of 8‌mm. The electric field vibrating y-direction has maximum magnitude of 60Vm−1. Choose the correct equations for electric and magnetic fields if the EM wave is propagating in vacuum :

[28-Jun-2022-Shift-2]

Ey=60‌sin[‌
π
4
×103(x−3×108t)]‌
∧
j
‌V‌m−1
Bz=2‌sin[‌
π
4
×103(x−3×108t)]‌
∧
k
‌T
Ey=60‌sin[‌
π
4
×103(x−3×108t)]‌
∧
j
‌V‌m−1
Bz=2×10−7‌sin[‌
π
4
×103(x−3×108t)]‌
∧
k
‌T
Ey=2×10−7‌sin[‌
π
4
×103(x−3×108t)]‌
∧
j
‌V‌m−1
Bz=60‌sin[‌
π
4
×103(x−3×108t)]‌
∧
k
‌T
Ey=2×10−7‌sin[‌
π
4
×104(x−4×108t)]‌
∧
j
‌V‌m−1
Bz=60‌sin[‌
π
4
×104(x−4×108t)]‌
∧
k
‌T

Validate

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