JEE Main 28 June 2022 Shift 2 Solved Paper

Section: Mathematics

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Question : 4 of 90

Marks: +1, -0

The term independent of x in the expansion of (1−x2+3x3)(‌

5

2

x3−‌

1

5x2

)11,x≠0 is :

[28-Jun-2022-Shift-2]

‌
7
40
‌
33
200
‌
39
200
‌
11
50

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