A water drop of radius 1 \mu {\m} falls in a situation where the effect of buoyant force is negligible. Co-efficient of viscosity of air is 1.8 \times 10^{-5} {\Nsm}^{-2} and its density is negligible as compared to that of water 10^6 {\gm}^{-3}. Terminal velocity of the water drop is (Take acceleration due to gravity =10 {\ms}^{-2} ) [28-Jun-2022-Shift-2]

Correct Answer is : 123.4×10−6ms−1

145.4 \times 10^{-6} {\ms}^{-1}

118.0 \times 10^{-6} {\ms}^{-1}

132.6 \times 10^{-6} {\ms}^{-1}

123.4 \times 10^{-6} {\ms}^{-1}

JEE Main 28 June 2022 Shift 2 Solved Paper

Section: Physics

Question : 37 of 90

Marks: +1, -0

A water drop of radius 1µm falls in a situation where the effect of buoyant force is negligible. Co-efficient of viscosity of air is 1.8×10−5Nsm−2 and its density is negligible as compared to that of water 106gm−3. Terminal velocity of the water drop is
(Take acceleration due to gravity =10ms−2 )

[28-Jun-2022-Shift-2]

145.4×10−6ms−1
118.0×10−6ms−1
132.6×10−6ms−1
123.4×10−6ms−1

Validate

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