JEE Main 28 June 2022 Shift 2 Solved Paper

Section: Mathematics

Question : 10 of 90

Marks: +1, -0

Let x=x(y) be the solution of the differential equation
2yex∕y2dx+(y2−4xex∕y2)dy=0 such that x(1)=0. Then, x(e) is equal to :

[28-Jun-2022-Shift-2]

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