The position vector of 1 {\kg} object is \overrightarrow{r}=(3 \stackrel{\^}{i}-\stackrel{\^}{j}) m and its velocity \overrightarrow{v}=(3 \stackrel{\^}{j}+\stackrel{\^}{k}) m s^{-1}. The magnitude of its angular momentum is \sqrt{x} {\Nm} where {\x} is ____ [28-Jun-2022-Shift-1]

JEE Main 28 June 2022 Shift 1 Solved Paper

Section: Physics

Question : 55 of 90

Marks: +1, -0

The position vector of 1‌kg object is

→

=(3

−

)m and its velocity

→

=(3

)ms−1. The magnitude of its angular momentum is √x‌Nm where x is ____

[28-Jun-2022-Shift-1]

Go to Question:

Prev Question

Next Question