Motion of a particle in x-y plane is described by a set of following equations x=4 \sin (\frac{\pi}{2}-\omega t) m and y=4 \sin (\omega t) m. The path of the particle will be : [28-Jun-2022-Shift-1]

JEE Main 28 June 2022 Shift 1 Solved Paper

Section: Physics

Question : 33 of 90

Marks: +1, -0

Motion of a particle in x-y plane is described by a set of following equations x=4‌sin(‌

−ωt)‌m and y=4‌sin(ωt)‌m. The path of the particle will be :

[28-Jun-2022-Shift-1]

Go to Question:

Prev Question

Next Question