Let the lines y+2 x=\sqrt{11}+7 \sqrt{7} and 2 y+x=2 \sqrt{11}+6 \sqrt{7} be normal to a circle C:(x-h)^2+(y-k)^2=r^2. If the line \sqrt{11} y-3 x=\frac{5 \sqrt{77}{3}+11 is tangent to the circle C, then the value of (5 h-8 k)^2+5 r^2 is equal to [28-Jun-2022-Shift-1]

JEE Main 28 June 2022 Shift 1 Solved Paper

Section: Mathematics

Question : 30 of 90

Marks: +1, -0

Let the lines y+2x=√11+7√7 and 2y+x=2√11+6√7 be normal to a circle C:(x−h)2+(y−k)2=r2. If the line √11y−3x=‌

5√77

+11 is tangent to the circle C, then the value of (5h−8k)2+5r2 is equal to

[28-Jun-2022-Shift-1]

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