JEE Main 28 June 2022 Shift 1 Solved Paper
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Question : 11 of 90
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Let y = y ( x ) x ( 1 − x 2 )
+ ( 3 x 2 y − y − 4 x 3 ) = 0 , x > 1 y ( 2 ) = − 2 y ( 3 )
[28-Jun-2022-Shift-1]
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