JEE Main 28 Jan 2026 Shift 1 Paper Solved Paper

Section: Mathematics

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Question : 2 of 75

Marks: +1, -0

If g(x)=3x2+2x−3,f(0)=−3 and 4g(f(x))=3x2−32x+72, then f(g(2)) is equal to:

[28 Jan 2026 Shift 1]

‌
7
2
−‌
25
6
‌
25
6
−‌
7
2

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