Let f: R-\{0\} \rightarrow(-\infty, 1) be a polynomial of degree 2 , satisfying f(x) f (\frac{1}{x}) =f(x)+f (\frac{1}{x}). If f(K)=-2 K, then the sum of squares of all possible values of K is : [28 Jan 2025 Shift 2]

JEE Main 28 Jan 2025 Shift 2 Paper

Section: Mathematics

Question : 20 of 75

Marks: +1, -0

Let f:R−{0}⟶(−∞,1) be a polynomial of degree 2 , satisfying f(x)f(‌

)=f(x)+f(‌

). If f(K)=−2K, then the sum of squares of all possible values of K is :

[28 Jan 2025 Shift 2]

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