Let the equation of the circle, which touches x-axis at the point ( a, 0 ), a>0 and cuts off an intercept of length b on y-axis be x^2+y^2-\alpha x+\beta y+\gamma=0. If the circle lies below x-axis, then the ordered pair (2 a, b^2) is equal to [28 Jan 2025 Shift 1]

Correct Answer is : (α,β2−4γ)

JEE Main 28 Jan 2025 Shift 1 Paper

Section: Mathematics

Question : 2 of 75

Marks: +1, -0

Let the equation of the circle, which touches x-axis at the point ( a,0 ), a>0 and cuts off an intercept of length b on y-axis be x2+y2−αx+βy+γ=0. If the circle lies below x-axis, then the ordered pair (2a,b2) is equal to

[28 Jan 2025 Shift 1]

(α,β2+4γ)
(γ,β2−4α)
(γ,β2+4α)
(α,β2−4γ)

Validate

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